ECAD Workbench

Part of Analogue and filter calculators

RC Low-Pass Filter Calculator

Solve cutoff frequency, resistance, or capacitance for a first-order RC low-pass filter.

Inputs

Select which value to calculate from the first-order RC cutoff relationship.

Results

Cutoff frequency1.592kHz
Resistance1kΩ
Capacitance100nF
Time constant100µs

RC low-pass filtering attenuates frequencies above cutoff. Source and load impedance can shift the real response.

When to use it

Use an RC low-pass filter for simple first-order smoothing and bandwidth limiting

An RC low-pass filter passes low-frequency content and attenuates higher-frequency content. Use this calculator to solve cutoff frequency, resistance, capacitance, and the matching time constant for a first-pass analogue filter check.

Signal smoothing

Estimate a simple RC corner before checking the real source and load impedances.

ADC input filtering

Set a first-pass anti-noise filter, then verify ADC acquisition and source-impedance limits.

Control and reference nodes

Check slow control, reference, or bias nodes where first-order filtering is acceptable.

Equations and model

The calculator uses the ideal first-order RC cutoff relationship. It assumes the resistor and capacitor are the dominant elements setting the pole.

fc = 1 / (2πRC)

Cutoff frequency

The -3 dB corner frequency for an ideal first-order RC low-pass filter.

τ = R × C

Time constant

The same R and C also define the time-domain response of the network.

R = 1 / (2πfcC), C = 1 / (2πfcR)

Rearranged values

Use the target cutoff to solve for a practical resistor or capacitor value.

fc - Cutoff frequency

Unit: hertz (Hz)

Frequency where the ideal output amplitude is about 0.707 of the passband amplitude.

R - Resistance

Unit: ohms (Ω)

The effective series resistance that works with the capacitor to set the corner.

C - Capacitance

Unit: farads (F)

The shunt capacitor value in the first-order RC low-pass network.

τ - Time constant

Unit: seconds (s)

The related time-domain settling constant of the same RC pair.

Worked example

This example matches the shared RC cutoff calculation already covered by the calculator test suite.

Design question: A 1 kΩ resistor and 100 nF capacitor form a simple low-pass filter. What is the cutoff frequency?

Inputs: R = 1 kΩ, C = 100 nF.

Time constant: τ = R × C = 100 µs.

Cutoff: fc = 1 / (2π × 1 kΩ × 100 nF) = 1.59 kHz.

Next check: confirm the source impedance, load impedance, component tolerance, and whether the filter response is acceptable at the frequencies that matter.

Source and load impedance limits

The simple equation is useful, but the real circuit decides which resistance the capacitor actually sees.

Source-side effects

  • Driver output impedance can add to the filter resistor.
  • Large source resistance can change cutoff and settling time.
  • Sampled inputs can disturb the capacitor between acquisitions.

Load-side effects

  • Finite load resistance can attenuate the passband signal.
  • Input capacitance can add to the intended capacitor.
  • Bias current and leakage can create DC error with large resistors.

Assumptions and limitations

First-order only

The model covers one ideal RC pole. It does not model higher-order filters or active filter behaviour.

Tolerance shifts cutoff

Capacitor tolerance, dielectric effects, and resistor tolerance can move the actual cutoff substantially.

Not a stability check

If the filter interacts with op-amp outputs, regulator loops, or ADC sampling, perform the relevant stability or settling checks.

Related calculators and next checks

Follow the next check based on whether the RC network is acting as a filter, delay, coupling network, or part of an amplifier path.

FAQ

What happens at the cutoff frequency?

For an ideal first-order RC low-pass filter, the output amplitude is about 70.7% of the low-frequency value, which is -3 dB. The response keeps rolling off above that point.

Does source impedance affect the cutoff?

Yes. The effective resistance is not always just the visible resistor. Source resistance, output impedance, and any series resistance can shift the real cutoff.

Does load impedance affect the cutoff?

Yes. If the load resistance is not high compared with the filter impedance, it changes gain and corner frequency. Buffering or a lower impedance filter may be needed.

Engineering reference

Equations, assumptions, and design guidance

Exact equation

Solves the ideal first-order RC low-pass cutoff relationship.

Equations and variables
Cutoff frequencyfc = 1 / (2 * pi * R * C)
Time constanttau = R * C
fc
Cutoff frequency (Hz)
R
Resistance (ohm)
C
Capacitance (F)
Assumptions and limitations

Assumptions

  • The source and load impedances do not shift the effective resistance.
  • The capacitor is ideal across the frequency range of interest.

Limitations

  • Component tolerance, capacitor ESR/ESL, op-amp input impedance, and source/load interaction are not included in this nominal solve.
Worked example and design use

1 kOhm and 100 nF filter

Inputs: R = 1 kOhm, C = 100 nF

Outputs: fc is about 1.59 kHz, tau = 100 us

Design guidance

  • Keep the cutoff well below unwanted high-frequency content and above the wanted passband edge.
  • Check R and C tolerances when cutoff placement is critical.