ECAD Workbench

Part of Circuit and resistor calculators

Loaded Voltage Divider Calculator

See how a real load changes divider output voltage, current, and accuracy.

Inputs

Compare an ideal divider with the same divider connected to a finite load.

Results

Loaded output voltage2.381V
Ideal output voltage2.5V
Loading error4.762%
R2 ∥ load9.091kΩ
Source current261.9µA
Load current23.81µA

A load comparable to R2 pulls the output downward. This matters for ADC inputs, bias networks, references, and any following stage with finite input resistance.

When to use it

Use the loaded divider check whenever Vout drives a real input

An ideal divider assumes no output current is drawn. Real ADC inputs, bias networks, references, enable pins, measurement instruments, and following stages can present finite resistance and change the divider output.

ADC and sense inputs

Check whether the divider is stiff enough before using the result as a measurement input.

Bias networks

Check output movement when another resistor network is connected to the divider node.

High-value dividers

Large divider resistors save current but are more sensitive to leakage, bias current, and loading.

Equations and practical model

The loaded divider model replaces the bottom resistor with the parallel combination of R2 and the load, then recalculates the divider output.

Videal = Vin × R2 / (R1 + R2)

Ideal divider output

The unloaded output before the following circuit is connected.

Req = R2 ∥ Rload

Loaded lower leg

The load resistance appears in parallel with the bottom divider resistor.

Vloaded = Vin × Req / (R1 + Req)

Loaded output

The actual output after the load changes the lower-leg resistance.

Rload - Load resistance

Unit: ohms (Ω)

The resistance presented by the following input, bias network, or measurement circuit.

Req - Equivalent lower resistance

Unit: ohms (Ω)

R2 in parallel with the load resistance.

Iload - Load current

Unit: amps (A)

Current drawn by the following circuit from the divider output node.

Error - Loading error

Unit: percent (%)

How far the loaded output falls below the ideal unloaded output.

Worked example

The example below is checked against the shared loaded-divider calculation helper used by the calculator.

Design question: A 5 V divider uses R1 = 10 kΩ and R2 = 10 kΩ. What happens when it drives a 10 kΩ load?

Ideal output: Videal = 5 V × 10 kΩ / (10 kΩ + 10 kΩ) = 2.5 V.

Loaded lower leg: R2 ∥ Rload = 10 kΩ ∥ 10 kΩ = 5 kΩ.

Loaded output: Vloaded = 5 V × 5 kΩ / (10 kΩ + 5 kΩ) = 1.667 V.

Loading error: the output falls by about 33.3% compared with the ideal value.

Load current: Iload = 1.667 V / 10 kΩ = 166.7 µA.

Equivalent resistance and Thevenin view

A voltage divider can be viewed as a source with an output resistance. The connected load forms another divider with that output resistance, which is why high-value dividers are easy to disturb.

At the output node

  • The ideal output is the open-circuit voltage.
  • The divider output resistance is R1 in parallel with R2.
  • A finite load makes another divider with that output resistance.

Design implication

  • Lower divider resistance gives a stiffer output but wastes more current.
  • Higher divider resistance saves current but increases loading error.
  • Buffers or different resistor values may be needed when the error is too high.

Assumptions and limitations

Static load model

The load is treated as a fixed resistance. Switched, sampled, or capacitive inputs need extra timing analysis.

No tolerance corners

The calculator shows nominal error. Resistor tolerance, leakage, bias current, and input-voltage variation can move the result further.

Not an ADC settling check

ADC inputs can also require source-impedance and acquisition-time checks that are not captured by a DC resistance model.

Related calculators and next checks

Follow the next check based on whether the problem is ideal ratio, power, tolerance, or a following input that needs a better model.

FAQ

Why does the load usually pull the divider output down?

The load resistance is effectively in parallel with R2. That makes the lower leg smaller, so the divider ratio decreases and the output voltage falls below the ideal unloaded value.

What load resistance is high enough?

There is no universal value. If the load resistance is much larger than the divider output resistance, the error may be small. For real design work, calculate the error instead of relying on a fixed rule.

Is an ADC input just a resistance?

Not always. Some ADC inputs are dynamic loads because of sampling capacitors and acquisition timing. This calculator is a static resistance model, so fast or high-impedance ADC inputs may need a settling-time check too.

Engineering reference

Equations, assumptions, and design guidance

Exact equation

Models an ideal DC voltage divider with a finite resistive load in parallel with the lower divider resistor.

Equations and variables
Effective lower legReq = R2 || Rload
Loaded outputVout = Vin * Req / (R1 + Req)
Loading errorerror = (Videal - Vout) / Videal
Vin
Input voltage (V)
R1
Top resistor (ohm)
R2
Bottom resistor (ohm)
Rload
Load resistance (ohm)
Assumptions and limitations

Assumptions

  • The load is resistive and static.
  • The source is ideal and DC.
  • Resistors are nominal values.

Limitations

  • Input bias current, ADC sampling capacitance, leakage, and resistor tolerance are not included here.
  • Use the voltage-divider set-point workflow for tolerance-aware preferred-value selection.
Worked example and design use

10 k / 10 k divider loaded by 100 k

Inputs: Vin = 5 V, R1 = 10 kOhm, R2 = 10 kOhm, Rload = 100 kOhm

Outputs: Loaded output is lower than the ideal 2.5 V result, R2 || Rload is reported for loading review

Design guidance

  • Keep the load resistance much larger than the divider Thevenin resistance when the divider ratio must remain accurate.
  • Check loaded divider current against source and power budget limits.