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Linear Regulator Thermal Calculator

Estimate linear regulator or LDO junction temperature, thermal margin, and maximum current from electrical loss and thermal path assumptions.

Inputs and tolerances

Estimate steady-state junction temperature, thermal margin, and maximum current for a linear regulator or LDO.

Calculate
Input voltage (V)
Output voltage (V)
Output current (A)
Quiescent current (A)
Ambient temperature (°C)
Maximum junction temperature (°C)
Thermal path
θJA junction-to-ambient (°C/W)

θJA is strongly board dependent. Datasheet values often assume a specific test PCB, copper area, airflow, and mounting condition that may not match the final product.

Thermal result

Estimated junction temperature95°CRange: 65.32°C to 135.88°C
Maximum output current200mARange: 160mA to 240mA
Required total thermal resistance50°C/WRange: 40°C/W to 60°C/W
Maximum ambient temperature25°CRange: 25°C to 25°C
Thermal margin30°CRange: -10.88°C to 59.68°C
Temperature rise70°CRange: 40.32°C to 110.88°C
Regulator dissipation1.4WRange: 1.008W to 1.848W
Load-related loss1.4WRange: 1.008W to 1.848W
Quiescent-current loss0WRange: 0W to 0W
Ideal efficiency41.667%Range: 38.889% to 44.737%
Maximum allowable dissipation2WRange: 1.6667W to 2.5W
Thermal estimate passes the selected limit. Still check datasheet limits, copper area, airflow, and transient thermal behaviour before release.

This is a steady-state lumped thermal estimate. It does not model transient thermal impedance, pulsed loads, copper spreading in detail, airflow variation, package hot spots, thermal shutdown, or regulator safe operating area.

Thermal margin

Convert linear-regulator loss into junction-temperature margin

Electrical dissipation tells you how many watts the regulator must lose. Thermal resistance, ambient temperature, and junction-temperature limit tell you whether that operating point is realistic.

θJA board estimate

Use a single junction-to-ambient value for quick package and PCB feasibility checks.

Case and heatsink path

Sum junction-to-case, interface, and sink-to-ambient resistances when that path dominates heat flow.

Maximum current estimate

Work backwards from allowable dissipation to estimate the thermal current limit for the entered conditions.

Worked example

For 12 V to 5 V at 200 mA, with 5 mA quiescent current, the regulator dissipates 1.46 W. With θJA = 50 °C/W and 25 °C ambient, the estimated junction temperature is 98 °C.

Power loss

Load-related loss = (12 V - 5 V) x 0.2 A = 1.4 W.

Quiescent loss = 12 V x 0.005 A = 0.06 W.

Total dissipation = 1.46 W.

Temperature rise

Temperature rise = 1.46 W × 50 °C/W = 73 °C.

Estimated junction temperature = 25 °C + 73 °C = 98 °C.

Margin to 125 °C = 27 °C.

Common mistakes and limits

Treating θJA as universal

θJA depends on package, copper area, vias, airflow, board stack-up, enclosure, and the datasheet test board.

Ignoring quiescent current

High-input-voltage LDOs can add meaningful heat from Vin x Iq, especially in always-on rails.

Using steady-state for pulses

Transient loads need transient thermal impedance or measured temperature, not only a steady-state lumped model.

Related calculators and next checks

Engineering reference

Equations, assumptions, and design guidance

Engineering approximation

Estimates steady-state linear regulator junction temperature, thermal margin, and maximum output current from electrical dissipation and a lumped thermal path.

Equations and variables
Regulator dissipationPd = (Vin - Vout) * Iout + Vin * Iq
θJA junction temperatureTj = Ta + Pd × θJA
Case and heatsink pathTj = Ta + Pd × (θJC + θCS + θSA)
Maximum dissipationPdmax = (Tjmax - Ta) / thetaTotal
Vin
Regulator input voltage (V)
Vout
Regulator output voltage (V)
Iout
Output load current (A)
Iq
Regulator quiescent current (A)
Ta
Ambient temperature (°C)
Tjmax
Maximum junction temperature (°C)
θ
Thermal resistance (°C/W)
Assumptions and limitations

Assumptions

  • The regulator is a linear regulator or LDO, not a switching regulator.
  • The thermal model is steady-state and lumped into one total thermal resistance.

Limitations

  • Transient thermal impedance, copper spreading detail, airflow variation, package hot spots, thermal shutdown, current limit, dropout, safe operating area, and manufacturer-specific derating are not modelled.
Worked example and design use

12 V to 5 V at 200 mA with θJA = 50 °C/W

Inputs: Vin = 12 V, Vout = 5 V, Iout = 0.2 A, Iq = 5 mA, Ta = 25 °C

Outputs: Pd = 1.46 W, temperature rise = 73 °C, Tj = 98 °C, margin to 125 °C = 27 °C

Design guidance

  • Use this estimate before selecting a package or deciding whether a buck converter is required.
  • Check the datasheet thermal test conditions and final PCB copper before treating θJA as reliable.